Having problems with your 1991 Jeep Cherokee Limited ?

I have to hold the ignition over to keep my 91 jeep running

\015 When i start my jeep it dies unless i hold the ignition over in the start position\015 Posted / edited by AnonymousUser on : 19-02-2018

Answers :

Ballast resistor has burnt out
This is a small resistor on the coil or in the coil feed wire that gives the coil a full 12 V when starting and cuts it back to about 8 V when it is running. This lessens the load on the coils.
Sometimes it can be found as an enlargement in the wires to the coil, sometimes it is a white porcelain resistor attached to the coil ( 1cm square and about 5
cm long ) and sometimes it is built into the coil.
In the last case the coil will have an "R" designation.

the fuel pump on the EFI model will only run for a few seconds unless it receives a signal that the motor is running. ( If you hit a tree say, the key is on, but because the motor is not running, the fuel pump will stop. Good thing too. )
This generally works off oil pressure, air flow through the air flow meter, or a combination.

If it stops if you let go of the key IMMEDIATELY, ie: in less than 3 secs, changing the coil would be a great cheap place to start.

If it is the fuel pump safety circuit, it should run for a couple or three seconds each time.

I would be finding the ballast resistor first and if it an "R" type coil, change that and see what happens.
This is normally a problem with the ballast resistor or associated wiring.
\015\012On some vehicles, in order to give a stronger spark during starting, which helps the engine to start, the ignition coil is designed to run normally on about 9 volts. As a car's electrical system runs on 12 volts, a ballast resistor is included in the coil's electrical connection to "drop" the 3 volt differnece. When the key is turned to the start position, the full 12 volts is applied to the coil for as long as the engine takes to start (giving a much stronger spark), and when the key is released back to the normal "on" position, the ballast resistor is automatically switched in to the coil circuit - if the coil was over-run on 12 volts all the time it would soon burn out.
\015\012Depending on your skills, and whether you have access to a tech manual or not, this isnt too difficult to fix. Otherwise a small independant garage shouldnt charge too much to fix this sort of probelm.
Repair Help & Product Troubleshooting for 1991 Jeep Cherokee Limited

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