Having problems with your 1991 Jeep Cherokee Limited ?

I have to hold the ignition over to keep my 91 jeep running

\015 When i start my jeep it dies unless i hold the ignition over in the start position\015 Posted / edited by AnonymousUser on : 20-11-2017

Answers :

Ballast resistor has burnt out
This is a small resistor on the coil or in the coil feed wire that gives the coil a full 12 V when starting and cuts it back to about 8 V when it is running. This lessens the load on the coils.
Sometimes it can be found as an enlargement in the wires to the coil, sometimes it is a white porcelain resistor attached to the coil ( 1cm square and about 5
cm long ) and sometimes it is built into the coil.
In the last case the coil will have an "R" designation.

OR
the fuel pump on the EFI model will only run for a few seconds unless it receives a signal that the motor is running. ( If you hit a tree say, the key is on, but because the motor is not running, the fuel pump will stop. Good thing too. )
This generally works off oil pressure, air flow through the air flow meter, or a combination.

If it stops if you let go of the key IMMEDIATELY, ie: in less than 3 secs, changing the coil would be a great cheap place to start.

If it is the fuel pump safety circuit, it should run for a couple or three seconds each time.

I would be finding the ballast resistor first and if it an "R" type coil, change that and see what happens.
This is normally a problem with the ballast resistor or associated wiring.
\015\012On some vehicles, in order to give a stronger spark during starting, which helps the engine to start, the ignition coil is designed to run normally on about 9 volts. As a car's electrical system runs on 12 volts, a ballast resistor is included in the coil's electrical connection to "drop" the 3 volt differnece. When the key is turned to the start position, the full 12 volts is applied to the coil for as long as the engine takes to start (giving a much stronger spark), and when the key is released back to the normal "on" position, the ballast resistor is automatically switched in to the coil circuit - if the coil was over-run on 12 volts all the time it would soon burn out.
\015\012
\015\012Depending on your skills, and whether you have access to a tech manual or not, this isnt too difficult to fix. Otherwise a small independant garage shouldnt charge too much to fix this sort of probelm.
Repair Help & Product Troubleshooting for 1991 Jeep Cherokee Limited

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